Here, we want to solve the system of linear equations by substitution
What we have to do here since we have the value of y already is to substitute the value of y into the first equation
We have this as follows;
[tex]\begin{gathered} 6x\text{ + 8(-5) = -22} \\ 6x\text{ - 40 = -22} \\ 6x\text{ = -22 + 40} \\ 6x\text{ = 18} \\ x\text{ = }\frac{18}{6} \\ x\text{ = 3} \end{gathered}[/tex]