GIVEN
The function representing the path of the ball is given to be:
[tex]h(t)=-5t^2+14t+3[/tex]
SOLUTION
The time taken to hit the ground can be calculated by equating the function to 0:
[tex]h(t)=0[/tex]
Therefore:
[tex]-5t^2+14t+3=0[/tex]
The quadratic equation can be solved as follows:
[tex]\begin{gathered} Factor\text{ the equation:} \\ -\left(5t+1\right)\left(t-3\right)=0 \\ Apply\text{ the zero factor principle} \\ \therefore \\ 5t+1=0,t=-\frac{1}{5} \\ or \\ t-3=0,t=3 \end{gathered}[/tex]
Since the time can only be positive
