[tex]\begin{gathered} (x1,y1)=(0,1) \\ (x2,y2)=(6,0) \\ \text{the slope is:} \\ m=\frac{y2-y1}{x2-x1}=\frac{0-1}{6-0}=-\frac{1}{6}_{} \end{gathered}[/tex]
Using the point-slope equation:
[tex]\begin{gathered} y-y1=m(x-x1) \\ y-1=-\frac{1}{6}x-0 \\ y=-\frac{1}{6}x+1 \end{gathered}[/tex]
since the values are above the line:
[tex]y>-\frac{1}{6}x+1[/tex]
