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Function g is a transformation of the parent function fx) = x2. The graph of g is a translation right 3 units and down 5 units of the graph off. Whatis the equation of function g written in the form y = ax + bx + c?

Respuesta :

[tex]f(x)=x^2[/tex]

Since f(x) is translated 3 units right that means x will change to (x - 3)

Since f(x) is translated down 5 units that means f(x) is subtracted by 5

So:

[tex]g(x)=(x-3)^2-5[/tex]

x changed to (x - 3) and f(x-3) changed to f(x-3) - 5

Since f(x) = x^2 so f(x - 3) = (x - 3)^2

Since f(x - 3) -5 = (x - 3)^2 - 5

So g(x) = (x - 3)^2 - 5

This is the vertex form

But the question asks for y = ax^2 + bx + c

So we must change it

g(x) = y

[tex]y=(x-3)^2-5[/tex]

Solve the bracket

[tex](x-3)^2=(x-3)(x-3)=(x)(x)+(x)(-3)+(-3)(x)+(-3)(-3)[/tex]

Add like terms

[tex](x-3)^2=x^2-3x-3x+9=x^2-6x+9[/tex][tex]\begin{gathered} y=x^2-6x+9-5 \\ y=x^2-6x+4 \end{gathered}[/tex]

g(x) is y=x^2 - 6x + 4

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