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HOMEWORK QUESTION: *A 0.01 kg bullet is fired at 250 m/s into a wooden block that is fixed. The bullet emerges from the block with a speed of 120 m/s. What is the change in momentum of the bullet?

Respuesta :

We will have the following:

First, we calculate the momentum before and after, that is:

[tex]\tau_1=(0.01kg)(250m/s)\Rightarrow\tau_1=2.5kg\ast m/s[/tex][tex]\tau_2=(0.01)(120m/s)\Rightarrow\tau_2=1.2kg\ast m/s[/tex]

So, the change in momentum is:

[tex]\delta\tau=1.2kg\ast m/s-2.5kg\ast m/s\Rightarrow\delta\tau=-1.3kg\ast m/s[/tex]

So, the change in momentum is -1.3kg*m/s.

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