Answer:
D. -28 m/s
Explanation:
To find the final speed, we will use the following equation
[tex]v_f^2=v_i^2+2g\Delta y[/tex]
Where vf is the final velocity, vi is the initial vertical velocity, g is the acceleration due to gravity and Δy is the height.
Replacing vi = 0 m/s, g = 9.8 m/s², and Δy = 40 m, we get
[tex]\begin{gathered} v_f^2=0^2+2(9.8)(40) \\ v_f^2=784 \\ v_f=\sqrt{784} \\ v_f=28 \end{gathered}[/tex]
Therefore, the vertical component of the velocity is vf = -28 m/s because the bullet is going down.
So, the answer is
D. -28 m/s
