Given the expression:
[tex]x^2-2x-3=0[/tex]
We will rewrite the expression to be as the form (x - a)² = b
So, we need to make a complete square
[tex]x^2-2x=3[/tex]
The coefficient of x = -2
Half the coefficient = -1
Square it will give 1
So, add (1) to both sides of the equation
[tex]x^2-2x+1=3+1[/tex]
Factor the left side of the equation, it is a complete square
[tex](x-1)^2=4[/tex]
Compare the result to the given form.
So, the answer will be:
[tex]a=1,and,b=4[/tex]
