We know that Cot # = 1/Tan#
Thus, the equation would be
Tan 2B = 1/Tan2B
[tex]\begin{gathered} \text{Tan}2B\text{ }\times Tan2B\text{ = 1} \\ \text{Tan}^22B\text{ = 1} \\ \text{Taking square root of both sides, it becomes} \\ \text{Tan}2B\text{ = }\sqrt[]{1}\text{ = 1} \\ 2B\text{ = }\tan ^{-1}(1) \\ 2B\text{ = 45} \\ B\text{ = }\frac{45}{2} \\ B\text{ = 22.5} \end{gathered}[/tex]B = 22.5 degrees
