Respuesta :
The start value of a function is the y-intercept of the function, f(x=0).
1. C(f=0)=8/9f+32
C(f=0)=32 --> the start value of the function
Growth value would be 8/9, because it's a linear function and that's the constant rate of change.
2. In this case, is exactly the same analysis:
y=4000-250x
Start value of the function would 4000 because it's the output value when x=0, that means the y-intercept. And the growth value would be -250 because it's the rate of change of the linear function.
3. Since we have the value tables, we can create the equation of the linear function:
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-5-(-9)}{0-(-3)}=\frac{4}{3} \\ y+3=m(x+9) \\ y=\frac{4}{3}x+12-3 \\ y=\frac{4}{3}x+9 \end{gathered}[/tex]By that, the start value of the function would be y(0)=9, and the growth value would be 4/3
4. We can do the same thing with the other value table:
[tex]\begin{gathered} m=\frac{9-3}{0-(-4)}=\frac{3}{2} \\ y-3=\frac{3}{2}(x+4) \\ y=\frac{3}{2}x+6+3 \\ y=\frac{3}{2}x+9 \end{gathered}[/tex]The start value of the function would be y(0)=9, and the growth value would be 3/2
