Solution:
To find the equation of a circle in standard form, the formula is
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ Where \\ (h,k)\text{ is the center and r is the radius} \end{gathered}[/tex]Given that;
[tex]\begin{gathered} (h,k)=(3,9) \\ r=8 \end{gathered}[/tex]Substitute the values of h, k and r into the formula above
[tex](x-3)^2+(y-9)^2=8^2[/tex]Hence, the equation of the circle in standard form is
[tex](x-3)^{2}+(y-9)^{2}=8^{2}[/tex]