From the properties of the square root, the given expression can be rewritten as:
[tex]\frac{\sqrt{3}}{\sqrt{16}}*\frac{\sqrt{3}}{\sqrt{9}}[/tex]
since
[tex]\begin{gathered} \sqrt{16}=4 \\ and \\ \sqrt{9}=3 \end{gathered}[/tex]
our last expression is equivalent to
[tex]\frac{\sqrt{3}}{4}*\frac{\sqrt{3}}{3}[/tex]
By making the product, it yields
[tex]\frac{\sqrt{3}*\sqrt{3}}{12}[/tex]
Now, since
[tex]\sqrt{3}*\sqrt{3}=\sqrt{3*3}=3[/tex]
our expression is equivalen to
[tex]\frac{3}{12}[/tex]
Finally , by comparing this result with the given options, the answer is option A.
