On the plane, the triangle is
On the second quadrant, all the points have the form (-x,y)
Therefore, the x-coordinates of the three points have to be negative and their y-coordinates have to be positive.
Then,
[tex]\begin{gathered} (10,-6)\to(10-11,-6+7)=(-1,1) \\ (6,2)\to(6-7,2)=(-1,2) \\ (4,-1)\to(4-5,-1+2)=(-1,1) \end{gathered}[/tex]
Therefore, we need to translate the image 11 units to the left and 7 units up so that point P is in the second quadrant. If P is in it, Q and R are too.
The answer is a translation by 11 units left and 7 units up (There is an infinite number of transformations that satisfy the condition stated in the problem)
