We need to obtain the formula of the line
General formula of the line
[tex]y=mx+b[/tex]where m is the slope and b the y-intercept
First, if the line is parallel to
[tex]y=\frac{1}{2}x-3[/tex]has the same slope(1/2)
then we have the slope of the new line, we can replace on the general formula
[tex]y=\frac{1}{2}x+b[/tex]to find b or y-intercept we can replace the point of the statement on this way we obtain b and we make sure that the new graph passes through this point
then
[tex](0)=\frac{1}{2}(-4)+b[/tex]and solve to b
[tex]\begin{gathered} 0=-\frac{4}{2}+b \\ b=\frac{4}{2} \\ \\ b=2 \end{gathered}[/tex]now we replace the slope and b on the formula
Graph
[tex]y=\frac{1}{2}x+2[/tex]now we need to points to graph, we have (-4,0) and the point of the y-intetrcept(the value of b is where x=0)
point of y intercept is (0,2)
we place the two points on the graph and join
