The balanced reaction for this reaction is:
[tex]Zn_{(s)}+H_2SO_{4(aq)}\rightarrow ZnSO_{4(aq)}+H_{2(g)}[/tex]Step 1: We will convert the mass of the Zn metal to moles:
[tex]\begin{gathered} moles=\frac{mass}{molar\text{ }mass} \\ \\ moles=\frac{45.1g}{65.38gmol^{-1}} \\ \\ moles=0.689813\text{ }moles\text{ }Zn \end{gathered}[/tex]Step 2: We will determine the moles of hydrogen gas that is produced from 0.689813 moles of Zn:
[tex]\begin{gathered} mole\text{ }ratio=1\text{ }Zn:1\text{ }H_2 \\ Therefore,0.689813\text{ }moles\text{ }Zn=0.689813\text{ }moles\text{ }H_2 \end{gathered}[/tex]Step 3: In order to determine the volume of gas we use the ideal gas law:
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