The balance after the end of 10 years is $6,554.47
Explanation:The amount after t years is given as:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]Principal, P = $4000
Interest rate, r = 5% = 5/100 = 0.05
Number of times compounded annually, n = 2
Time, t = 10 years
[tex]\begin{gathered} A=4000(1+\frac{0.05}{2})^{2\times10} \\ \\ =4000(1.025)^{20} \\ \\ =6554.47 \end{gathered}[/tex]The balance after the end of 10 years is $6,554.47
