To solve the exercise you can use the point-slope formula, that is,
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{ Where m is the slope of the line and} \\ (x_1,y_1)\text{ is a point through which the line passes} \end{gathered}[/tex]
So, in this case, you have
[tex]\begin{gathered} m=\frac{1}{4} \\ (x_1,y_1)=(6,3) \end{gathered}[/tex][tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{ Replace} \\ y-3_{}=\frac{1}{4}(x-6_{}) \\ y-3_{}=\frac{1}{4}x-\frac{1}{4}\cdot6_{} \\ \end{gathered}[/tex]
