Given:
[tex]\begin{gathered} 3x+3y=3\ldots\ldots(1) \\ y=-\frac{1}{2}x+2\ldots\ldots(2) \end{gathered}[/tex]
Multiply by 6 into equation (2) as,
[tex]\begin{gathered} 6y=-3x+12 \\ 3x+6y=12\ldots\text{.}\mathrm{}(3) \end{gathered}[/tex]
Now, (1) - (3), then
[tex]\begin{gathered} 3x+3y-6y-3x=3-12 \\ -3y=-9 \\ 3y=9 \\ y=3 \end{gathered}[/tex]
Hence, the value of y=3.
