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In a three-person tug-of-war, three ropes are tied at a pointGary is pulling due East with a force of 650 Newtons, lune is pulling due North with a force of 450 Newtons, and Levi is pulling the third rope. The knot in the middle is not moving. What is the magnitude of Levi's effort?A.34.7B.55.3C.500D.790.6

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EXPLANATION

The force applied by PointGary is 650N due East.

Assuming that x represent the unknown magnitude for x-force for Levi ad y represent the y-force, we can apply the following reasoning:

x-component 0 = 0 -650 + x

y-component 0 = 450 + 0 - y

Now, we can see that:

x = 650

y = 450

Now, we can determine the magnitude:

Levi's Magnitude=

[tex]=\sqrt[]{(650)^2+(450)^2}=790.6N[/tex]

The solution is the OPTION D.

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