start by writting the line in the slope-intercept form
[tex]\begin{gathered} 4(y-3)=-\frac{4}{3}x-\frac{13}{2} \\ 4y-12=-\frac{4}{3}x-\frac{13}{2} \\ 4y=-\frac{4}{3}x-\frac{13}{2}+12 \\ 4y=-\frac{4}{3}x+\frac{11}{2} \\ y=-\frac{1}{3}x+\frac{11}{8} \end{gathered}[/tex]replace the coordinate x of the point to see if the point lies on the line, if the coordinate y is equal to the result then the point lies on the line
[tex]\begin{gathered} y=-\frac{1}{3}(-\frac{15}{8})+\frac{11}{8} \\ y=\frac{5}{8}+\frac{11}{8} \\ y=2 \end{gathered}[/tex]Since 2 is different from -4 then the point does not lie on the line.
