ANSWER
21.125 m
EXPLANATION
Assuming the bullet has a constant velocity of 4225 ft/s when fired, the distance it travels in t seconds is:
[tex]\begin{gathered} v=\frac{d}{t} \\ d=v\cdot t \end{gathered}[/tex]If we want to find the distance in 5 ms, we have to multiply it by the velocity but we have to use the same units:
[tex]5ms=0.005s[/tex]The distance is then:
[tex]d=4225\frac{ft}{s}\cdot0.005s=21.125m[/tex]