Tell whether the ordered pair is a solution of the inequality. I need help with these two that's why I put them.

Remember that an ordered pair is written in the form:
[tex](x,y)[/tex]Substitute the given values of x and y into the inequality to see if it is true or false. In case that the inequality turns out to be true, then the ordered pair is a solution.
1. x-y>2; (5,4)
[tex]\begin{gathered} x-y>2 \\ \Rightarrow5-4>2 \\ \Rightarrow1>2 \end{gathered}[/tex]Since 1>2 is false, then (5,4) is not a solution for the inequality x-y>2-
3. 5x+y <= 12: (2,2)
[tex]\begin{gathered} 5x+y\le12 \\ \Rightarrow5(2)+2\le12 \\ \Rightarrow10+2\le12 \\ \Rightarrow12\le12 \end{gathered}[/tex]Since 12=12, then the last expression is true, then, (2,2) is a solution to the inequality.