What is the remainder when P(x) = x ¹²³ + x ⁵⁶ + 1 is divided by x-1.

In order to calculate the remainder of this division, we can use the remainder theorem.
This theorem states that when dividing p(x) by q(x), and q(x) has a zero x = k, the remainder of the division is given by r = p(k).
Since the division is by the polynomial x - 1 and its zero is x = 1, let's calculate the value of p(1), which will be the remainder of the division:
[tex]\begin{gathered} p(1)=1^{123}+1^{56}+1 \\ p(1)=1+1+1 \\ p(1)=3 \end{gathered}[/tex]Therefore the remainder of the division is 3.