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A 1kg rock is thrown straight upward in 20m/s neglecting air resistance the net force that acts on it when it’s half way to the top of its path is A9.8Cmore that’s 9.8B less than 9.8

Respuesta :

You can consider that the net force acting on the rock is the same in all its trajectory.

Moreover, take into account that the net force is due to the weight of the rock, which is:

W = m*g = (1 kg)(9.8m/s^2) = 9.8 N

Hence, the net force is 9.8N

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