Respuesta :

[tex]\begin{gathered} 2\lbrack32-(4-1)^3\rbrack \\ 2\lbrack32-(3)^3\rbrack \\ 2\lbrack32-27\rbrack\text{ }\left\lbrace where3^3\text{ = 27}\right\rbrace \\ 2\lbrack5\rbrack \\ =\text{ 10} \end{gathered}[/tex]