Respuesta :
Answer:
[tex]5y\text{ = -x + 11}[/tex]Explanation:
Mathematically, the equation of a straight line can be represented as:
[tex]y\text{ = mx + b}[/tex]where m is the slope of the line and b is the y-intercept of the line
When two lines are perpendicular, the product of their slope values equal to -1
From the given line, it has a slope of 5
So the slope of the line perpendicular to it will be:
[tex]\begin{gathered} m_2\times\text{ 5 = -1} \\ m_2\text{ = }\frac{-1}{5} \end{gathered}[/tex]Since we have a point on the given line, we can get the equation of the said line
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-2\text{ = -}\frac{1}{5}(x-1) \\ 5(y-2)\text{ = -1(x-1)} \\ 5y-10\text{ = -x + 1} \\ 5y=-x+1\text{ + 10} \\ 5y\text{ = -x + 11} \end{gathered}[/tex]