[tex]\begin{gathered} \text{slope}_a=4 \\ \text{slope}_b=-\frac{3}{4} \end{gathered}[/tex]
Explanation
Step 1
when you have 2 points of a line (P1 and P2) you can find the slope using:
[tex]\begin{gathered} \text{slope}=\frac{\Delta y}{\Delta x}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_{1,}y_1) \\ P2(x_2,y_2) \end{gathered}[/tex]
then, for table 1 pick 2 points
Let
P1(1,2)
P2(3,10)
replace
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{10-2}{3-1}=\frac{8}{2}=4 \end{gathered}[/tex]
Step 2
now, for table b
Let
P1(-6,8)
P2(-2,5)
replace
[tex]\begin{gathered} \text{slope}=\frac{5-8}{-2-(-6)}=\frac{-3}{-2+6}=\frac{-3}{4}=-\frac{3}{4} \\ \text{slope}_b=-\frac{3}{4} \end{gathered}[/tex]
I hope this helps you
