So the equation that relates the height h and the length of the radius bone b of a woman is:
[tex]h=3.846b+72.5[/tex]
In exercise 31 we need to estimate the height of a woman with a 25cm long radius bone. This basically means taking b=25 and calculating h:
[tex]\begin{gathered} h=3.846b+72.5 \\ h=3.846\cdot25+72.5 \\ h=96.15+72.5 \\ h=168.65 \end{gathered}[/tex]
So the height is 168.65cm but we need to round it ti the nearest centimeter so the answer for 31 is h=169cm.
In exercise 32 we have to transform this quantity into inches by using the relation:
[tex]1in=2.54\operatorname{cm}[/tex]
For this purppose we can use the rule of three with this relation and h=169cm:
[tex]\begin{gathered} 2.54\operatorname{cm}\rightarrow1in \\ 169\operatorname{cm}\rightarrow x \end{gathered}[/tex]
According to the rule of three x, which is the woman's height in inches, is given by:
[tex]\begin{gathered} x=\frac{169\operatorname{cm}\cdot1in}{2.54\operatorname{cm}}=\frac{169\operatorname{cm}\cdot in}{2.54\operatorname{cm}}=\frac{169}{2.54}\cdot\frac{cm\cdot in}{\operatorname{cm}} \\ x=66.54in \end{gathered}[/tex]
Which means that the woman's height in inches is 66.54 but we need to round it to the nearest inch so the answer for 32 is h=67in.
