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ty86422Vertex:(5, 3)46(6,5)8XFinish the steps below to write a quadratic function forthe parabola shown.1. Use the vertex form, f(x) = a(x − h)² + k, andsubstitute in the values for h and k.f(x)= a(x-5)²+32. Use another point and substitute in valuesfor x and f(x). Solve for a.5= a(6-5)²+33. Write the function, using the values for h, k, and a.The function is f(x) =

ty86422Vertex5 346658XFinish the steps below to write a quadratic function forthe parabola shown1 Use the vertex form fx ax h k andsubstitute in the values for class=

Respuesta :

We need to finish the steps:

In step 2, we need to find the value of a:

[tex]5=a(6-5)^2+3[/tex]

Solve for a:

5=a(1)²+3

5=a+3

Subtract both sides 3:

5-3=a+3-3

2=a

Now, for step 3, we need to write the function using the values of h,k, and a:

[tex]f(x)=a(x-h)^2+k[/tex]

Where h=5, k=3, and a =2

Replacing, the answer is:

[tex]f(x)=2(x-5)^2+3[/tex]

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