SamrahM230427
SamrahM230427
29-10-2022
Mathematics
contestada
solve by factorization 48n^2 -3n^4=0
Respuesta :
CamaniT103450
CamaniT103450
29-10-2022
Given:-
[tex]48n^2-3n^4=0[/tex]
To find the value by factorization.
So now we simplify,
[tex]\begin{gathered} 48n^2-3n^4=0 \\ 3n^2(16-n^2)=0 \\ 3n^2=0,16-n^2=0 \\ n=0,n^2=16 \\ n=0,n=14 \end{gathered}[/tex]
So the values are 0 and 14.
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