Notice that we are dealing with a right triangle; therefore, we can use the following trigonometric identities
[tex]\sin \theta=\frac{O}{H},\cos \theta=\frac{A}{H},\tan \theta=\frac{O}{A}[/tex]
In our case,
[tex]M=\theta,O=\sqrt[]{651},A=5,H=26[/tex]
Thus,
[tex]\begin{gathered} \Rightarrow\sin M=\frac{\sqrt[]{651}}{26} \\ \Leftrightarrow\sin M\approx0.9813 \end{gathered}[/tex]
Similarly,
[tex]\begin{gathered} \cos M=\frac{5}{26} \\ \Leftrightarrow\cos M\approx0.1923 \\ \tan M=\frac{\sqrt[]{651}}{5} \\ \Leftrightarrow\tan M\approx5.1029 \end{gathered}[/tex]
