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2.On a frictionless air track, a 0.15 kg glider moving to the right collides with and sticks to a stationary 0.25kg glider. The net momentum of this system after the collision is 0.18 kg . m/s. What is the speed of thegliders after the collision?1.32 m/s0.45 m/s0.97 m/s0.66 m/s

Respuesta :

We have the next information

m1=0.15kg

m2=0.25kg

p=0.18kg m/s

because the two masses are sticks after the collision, first we sum the masses

[tex]m=m_1+m_2=0.15+0.25=0.4\text{ kg}[/tex]

then we use the momentum formula

[tex]p=m\cdot v[/tex]

then we substitute the values

[tex]0.18=0.4\cdot v[/tex]

then we isolate v

[tex]v=\frac{0.18}{0.4}=0.45^{}\frac{m}{s}[/tex]

the speed of the gliders after the collision is 0.45 m/s

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