We are asked to find the area of the target outside of the bullseye.
Recall that the area of a circular archery target is given by
[tex]A=\pi r^2[/tex]Where r is the radius.
The bullseye has a radius of 3 inches.
The area of the bullseye is given by
[tex]A_{}=\pi r^2=\pi\cdot3^2=9\pi\; in^2[/tex]The entire target has a radius of 9 inches.
The area of the entire target is given by
[tex]A_{}=\pi r^2=\pi\cdot9^2=81\pi\; in^2[/tex]Subtract the area of the bullseye from the entire target area to find the area of the target outside of the bullseye.
[tex]A=81\pi-9\pi=72\pi\; =226.1\; in^2[/tex]Therefore, the area of the target outside of the bullseye is 226.1 in^2
Option a. is the correct answer.
