Answer: [tex]distance\text{ = square root of 58 \lparen option D\rparen}[/tex]
Explanation:
Given:
Points: (3, -9) and (6, -2) on a coordinate plane
To find:
The distance between the two points
To determine the distance between the points, we will apply the formula:
[tex]$dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}$[/tex][tex]\begin{gathered} x_1=3,y_1=-9,x_2=6,y_2\text{ = -2} \\ dis\tan ce\text{ = }\sqrt{(-2-(-9))^2+(6-3)^2} \\ dis\tan ce\text{ = }\sqrt{(-2+9)^2+(6-3)^2} \\ dis\tan ce\text{ = }\sqrt{(7)^2+(3)^2} \end{gathered}[/tex][tex]\begin{gathered} distance\text{ = }\sqrt{49\text{ + 9}} \\ distance\text{ = }\sqrt{58} \end{gathered}[/tex]
