In the right triangles whose legs are a, b and its hypotenuse is c
[tex]a^2+b^2=c^2[/tex]
In triangle JLK
∵ LK and JL are the legs of the triangle
∵ KJ is the hypotenuse
[tex]\therefore(LK)^2+(JL)^2=(KJ)^2[/tex]
∵ KL = 14 m and KJ = 18 m
Substitute them in the rule above to find JL
[tex]\begin{gathered} (14)^2+(JL)^2=(18)^2 \\ 196+(JL)^2=324 \end{gathered}[/tex]
Subtract 196 from both sides
[tex]\begin{gathered} 196-196+(JL)^2=324-196 \\ (JL)^2=128 \end{gathered}[/tex]
Take a square root for both sides
[tex]\begin{gathered} \sqrt[]{(JL)^2}=\sqrt[]{128} \\ JL=11.3137085 \end{gathered}[/tex]
Round it to the nearest hundredth
[tex]\therefore JL=11.31m[/tex]
The answer is 11.31 m
