To determine the length of the other leg of the triangle, we would apply the pythagorean theorem which states that
Hypotenuse^2 = one leg^2 + other leg^2
From the information given,
hypotenuse = 6
one leg = 2
Thus, we have
[tex]\begin{gathered} 6^2=2^2+otherleg^2 \\ 36=4+otherleg^2 \\ \text{other leg}^2\text{ = 36 - 4 = 32} \\ \text{other leg = }\sqrt[\square]{32} \\ \text{other leg = 5}.66 \end{gathered}[/tex]The length of the other leg is 5.7 meters to one decimal place
