Answer:
D. 1/3
Explanations:
The given sequance is:
27, 9, 3, 1, .............................
For a geometric sequence:
[tex]T_1,T_2,T_3,T_4,\ldots\ldots\ldots..T_{n-1},T_n[/tex]
The common ratio is:
[tex]r\text{ = }\frac{T_2}{T_1}\text{ = }\frac{T_3}{T_2}=\frac{T_4}{T_3}=\ldots\text{..=}\frac{T_n}{T_{n-1}}[/tex]
For the sequence 27, 9, 3, 1
[tex]r\text{ = }\frac{9}{27}=\text{ }\frac{3}{9}=\text{ }\frac{1}{3}[/tex]
The common ratio = 1/3
