As given by the question
There are given that the equation
[tex]\begin{gathered} 2x+8y=5 \\ 24x-4y=-15 \end{gathered}[/tex]Now,
Solve the given system of equation by using substitution method
So,
First find the x from the first equation
Then,
From the first equation
[tex]\begin{gathered} 2x+8y=5 \\ 2x=5-8y \\ x=\frac{5-8y}{2}\ldots(a) \end{gathered}[/tex]Then,
Put the value of x from equation (a) into the equation second
So,
From the second equation
[tex]\begin{gathered} 24x-4y=-15 \\ 24(\frac{5-8y}{2})-4y=-15 \\ 60-96y-4y=-15 \\ 60-100y=-15 \\ -100y=-75 \\ y=\frac{75}{100} \\ y=\frac{3}{4} \end{gathered}[/tex]Now,
Put the value of y into the equation (a)
So,
From the equation (a)
[tex]\begin{gathered} x=\frac{5-8y}{2} \\ x=\frac{5-8(\frac{3}{4})}{2} \\ x=\frac{5-6}{2} \\ x=-\frac{1}{2} \end{gathered}[/tex]Hence, the value of x and y is shown below:
[tex]x=-\frac{1}{2}\text{ and y=}\frac{\text{3}}{4}[/tex]