Given
[tex]\begin{gathered} 15x+1=59 \\ 15x=59-1 \\ 15x=58 \\ x=\frac{58}{15} \\ x=3.87 \end{gathered}[/tex]at x=4, the expression on the left hand side will not be equal to the expression on the right hand side .
Hence x=4 is not a solution to the equation
LHS
15(4) + 1= 61
RHS= 59
59 and 61 aren't the same
