Use the table to match each conditional probability with the correct fraction

Answer:
Explanation:
(a)The probability that a randomly selected male student has brown eyes.
• The number of male students = 80
,• The number of male students with brown eyes = 38
[tex]\begin{gathered} P(\text{randomly selected male student has brown eyes\rparen}=\frac{38}{80} \\ =\frac{19}{40} \end{gathered}[/tex](b)The probability that a randomly selected female student has green eyes.
• The number of female students = 100
,• The number of female students with green eyes = 14
[tex]\begin{gathered} P(\text{randomly selected female student has green eyes\rparen}=\frac{14}{100} \\ =\frac{7}{50} \end{gathered}[/tex](c)The probability that a randomly selected student with blue eyes is male.
• The number of students with blue eyes = 22
,• The number of male students with blue eyes = 10
[tex]\begin{gathered} P(\text{randomly selected student with blue eyes is male\rparen}=\frac{10}{22} \\ =\frac{5}{11} \end{gathered}[/tex](d)The probability that a randomly selected student with green eyes is female.
• The number of students with green eyes = 26
,• The number of female students with green eyes = 14
[tex]\begin{gathered} P(\text{randomly selected student with green eyes is female\rparen}=\frac{14}{26} \\ =\frac{7}{13} \end{gathered}[/tex]