For the sequence required, we have that the middle even number is 6q, since there are five consecutive even numbers, then there are 2 even numbers before 6q and 2 even number after 6q. Then, we can write the following sequence:
[tex]6q-4,6q-2,6q,6q+2,6q+4[/tex]adding all these terms, we get the following:
[tex]\begin{gathered} (6q-4)+(6q-2)+(6q)+(6q+2)+(6q+4)= \\ 6q-4+6q-2+6q+6q+2+6q+4=30q \end{gathered}[/tex]therefore, the sum of the five numbers si 30q
