Solve by square root;
[tex](3x-2)^2=-12[/tex]We start by taking the square root of both sides, and we'll have;
[tex]\sqrt[]{(3x-2)^2}=\pm\sqrt[]{-12}[/tex]Note that the square root sign cancels out the square sign on the left side.
[tex]3x-2=\pm\sqrt[]{-12}[/tex]The square root of negative 12 can be splitup into the following;
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