How many grams of Kl are in 5.30x10^22 molecules of potassium iodide(Kl)?

Answer
14.6 g
Explanation
Given:
Number of molecules of KI = 5.30 x 10²² molecules
What to find:
The grams of KI present in 5.30 x 10²² molecules.
Step-by-step solution:
Step 1: Convert the moles of KI to moles using Avogadro's number.
Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules
Therefore, the moles of KI in 5.30 x 10²² molecules will be
[tex]\frac{5.30\times10²²\text{ }molecules}{6.022\times10²^3\text{ }molecules}\times1\text{ }mol\text{ }KI=0.088\text{ }mol\text{ }KI[/tex]Step 2: Use the mole formula to determine the mass of Ki in 0.088 mol KI.
Note: The molar mass of KI = 166 g/mol
[tex]\begin{gathered} Mole=\frac{Mass}{Molar\text{ }mass} \\ \\ \Rightarrow Mass=Mole\times Molar\text{ }mass \\ \\ Mass=0.088\text{ }mol\times166\text{ }g\text{/}mol \\ \\ Mass=14.608\text{ }g\approx14.6\text{ }g \end{gathered}[/tex]Therefore, 14.6 g of KI are in 5.30 x 10²² molecules of potassium iodide(Kl)