The figure is a rectangle plus a triangle. We know that the area of a rectangle is given by:
[tex]A_R=bh[/tex]
the area of the triangle is given by:
[tex]A_T=\frac{1}{2}bh[/tex]
for the rectangle we have that the base is v and its height is k. For the triangle we have a base of v and and a height of 9, therefore the total area is:
[tex]vk+\frac{1}{2}v(9)[/tex]
Hence the answer is the third option.
