Given:
The expression is,
[tex]\frac{1}{2}x+32=x+12+2x[/tex]The objective is to solve for x.
The value of x can be solved as,
[tex]\begin{gathered} \frac{1}{2}x+32=12+3x \\ \frac{x}{2}-3x=12-32 \\ \frac{x-3x(2)}{2}=-20 \\ \frac{x-6x}{2}=-20 \\ \frac{-5x}{2}=-20 \\ -5x=-20(2) \\ 5x=40 \\ x=\frac{40}{5} \\ x=8 \end{gathered}[/tex]Hence, the value of x is 8.
