Given data:
* The initial velocity of the rock is 5 m/s.
* The time taken by the rock is 7 seconds.
* The acceleration of the rock is,
[tex]g=9.8ms^{-2}[/tex]Solution:
By the kinematics equation,
The distance traveled by the rock in the vertical direction is,
[tex]y=y_o+v_ot+\frac{1}{2}gt^2[/tex]where y_o is the initial distance of the rock, y is the final distance after the time t, v_o is the initial velocity, and t is the time taken to reach the final distance,
Substituting the known values,
[tex]\begin{gathered} y=0+5\times7+\frac{1}{2}\times9.8\times7^2 \\ y=35+240.1 \\ y=275.1\text{ m} \end{gathered}[/tex]Thus, the distance traveled by the rock in 7 seconds is 275.1 meter.
