Respuesta :
Let n be the amount of pages of each type. Since pages of 1/4, 1/2 and full pages were bought in equal amounts, then the total amount of purchased paper is:
[tex]n\times\frac{1}{4}+n\times\frac{1}{2}+n\times1=(\frac{1}{4}+\frac{1}{2}+1)n[/tex]On the other hand, since each 1/4 page costs $200, each 1/2 page costs $350 and a full page $600, then the total amount of money spent on that is:
[tex]200n+350n+600n=1150n[/tex]The total is also equal to $11,500. Then:
[tex]\begin{gathered} 1150n=11,500 \\ \Rightarrow n=\frac{11,500}{1150} \\ \Rightarrow n=10 \end{gathered}[/tex]Then, substitute n=10 into the first expression to find the total amount of page space that was purchased:
[tex](\frac{1}{4}+\frac{1}{2}+1)\times10=\frac{7}{4}\times10=\frac{35}{2}=17.5[/tex]Therefore, the total amount of space that was purchased was:
[tex]17.5\text{ pages}[/tex]