[tex]0.2(d-6)=0.3d+5-3+0.1d[/tex]
To solve for d:
1. Remove parenthesis:
[tex]0.2d-1.2=0.3d+5-3+0.1d[/tex]
2. Leave the terms with d in one side of the equation:
-Add 1.2 in both sides of the equation:
[tex]\begin{gathered} 0.2d-1.2+1.2=0.3d+5-3+0.1d+1.2 \\ 0.2d=\text{0}.3d+5-3+0.1d+1.2 \end{gathered}[/tex]
-Substract 0.3d and 0.1d in both sides of the equation:
[tex]\begin{gathered} 0.2d-0.3d-0.1d=0.3d-0.3d+5-3+0.1d-0.1d+1.2 \\ 0.2d-\text{0}.3d-0.1d=5-3+1.2 \end{gathered}[/tex]
3. Opperate similar terms:
[tex]-0.2d=3.2[/tex]
4. Divide into (-0.2) both sides of the equation:
[tex]\begin{gathered} \frac{-0.2}{-0.2}d=\frac{3.2}{-0.2} \\ \\ d=-16 \end{gathered}[/tex]Then, d is -16
