In order to determine the distance traveled by the car, use the followin formula from kinematics:
[tex]x=v_ot+\frac{1}{2}at^2[/tex]where,
vo: initial speed = 25.21m/s
t: time = 4.36s
a: acceleration = ?
x: distance = ?
To calculate the distance x it is necessary to calculate the deceleration of the car. Use the following formula:
[tex]a=\frac{v-v_o}{t}=\frac{0\frac{m}{s}-25.21\frac{m}{s}}{4.36s}\approx-5.78\frac{m}{s^2}[/tex]Then, replace the values of t, vo and a into the expression for x and simplify:
[tex]x=(25.21\frac{m}{s})(4.36s)+\frac{1}{2}(-5.78\frac{m}{s^2})(4.36s)^2\approx54.98m[/tex]Hence, the distance traveled by the car before it stops is approximately 54.98m
