Answer:
$1.41
Explanation:
• In a standard deck, there are a total of 52 cards; and
,
• The number of Hearts = 13
First, we find the probability of drawing two hearts without replacement.
[tex]\begin{gathered} P(1st\text{ Heart)=}\frac{13}{52} \\ P(2nd\text{ Heart)=}\frac{12}{51} \\ P(\text{two hearts)}=\frac{13}{52}\times\frac{12}{51}=\frac{1}{17} \end{gathered}[/tex]
Next, find the probability of not drawing two hearts.
[tex]P(\text{not drawing two hearts)}=1-\frac{1}{17}=\frac{16}{17}[/tex]
So, we have that:
• You gain $600 with a probability of 1/17.
,
• You lose $36 with a probability of 16/17.
The expected value of your bet therefore is:
[tex]\begin{gathered} (600\times\frac{1}{17})+(-36\times\frac{16}{17}) \\ =\$1.41 \end{gathered}[/tex]
The expected value is $1.41.