INFORMATION:
We have the next compound:
[tex]Na_3NO_2[/tex]And we must find the oxidation state of the nitrogen.
STEP BY STEP EXPLANATION:
To find the oxidation state of an element, we need to use the next general rules
Now, using that in a neutral compound all oxidation numbers must add up to zero we have the next equation
[tex]oxidation\text{ }state\text{ }Na+oxidation\text{ }state\text{ }N+oxidation\text{ }state\text{ }O=0[/tex]Then, since the Na is on the group one of the periodic table, Na has a plus one oxidation number and for Oxygen is -2. So,
Oxidation state Na = number of Na in the compound(oxidation number) = 3(+1) = +3
Oxidation state N = x (we don't know it yet)
Oxidation state O = number of O in the compound(oxidation number) = 2(-2) = -4
Finally, replacing in the equation and solving for x
[tex]\begin{gathered} +3+x-4=0 \\ \text{ Solving for x,} \\ x-4=-3 \\ x=-3+4 \\ x=+1 \end{gathered}[/tex]ANSWER:
The oxidation state of the nitrogen in Na3NO2 is +1
